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The revenue function is given by $R(x) = 100x – x^2 – x^3$. Find the demand function. |
$P(x)=100−x−x^2$ $P(x)=100x−x^2−x^3$ $P(x)=100−2x−3x^2$ $P(x)=x(100−x−x^2)$ |
$P(x)=100−x−x^2$ |
The correct answer is Option (1) → $P(x)=100−x−x^2$ If $₹p$ is the price per unit, then total revenue = $R(x) = px$ $⇒ px = 100x - x^2-x^3$ (given) $⇒ p = 100-x-x^2$. The demand function = $100-x-x^2$. |
