Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(IV), (B)-(II), (C)-(III), (D)-(I) (A)-(IV), (B)-(II), (C)-(I), (D)-(III) (A)-(II), (B)-(IV), (C)-(I), (D)-(III) (A)-(II), (B)-(IV), (C)-(III), (D)-(I) |
(A)-(IV), (B)-(II), (C)-(I), (D)-(III) |
The correct answer is Option (2) → (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
$\text{For } \frac{dy}{dx}+P(x)\,y=Q(x),\ \text{I.F.}=e^{\int P(x)\,dx}$ $(A)\ \frac{dy}{dx}+2xy=1 \;\Rightarrow\; P(x)=2x \;\Rightarrow\; \text{I.F.}=e^{\int 2x\,dx}=e^{x^{2}}\ \Rightarrow\ (IV)$ $(B)\ x\frac{dy}{dx}+2xy=1 \;\Rightarrow\; \frac{dy}{dx}+2y=\frac{1}{x} \;\Rightarrow\; P(x)=2 \;\Rightarrow\; \text{I.F.}=e^{\int 2\,dx}=e^{2x}\ \Rightarrow\ (II)$ $(C)\ x\frac{dy}{dx}+y=1 \;\Rightarrow\; \frac{dy}{dx}+\frac{1}{x}y=\frac{1}{x} \;\Rightarrow\; P(x)=\frac{1}{x} \;\Rightarrow\; \text{I.F.}=e^{\int \frac{1}{x}\,dx}=x\ \Rightarrow\ (I)$ $(D)\ x\frac{dy}{dx}+2y=2 \;\Rightarrow\; \frac{dy}{dx}+\frac{2}{x}y=\frac{2}{x} \;\Rightarrow\; P(x)=\frac{2}{x} \;\Rightarrow\; \text{I.F.}=e^{\int \frac{2}{x}\,dx}=x^{2}\ \Rightarrow\ (III)$ Matching: $(A)\!\to\!(IV),\ (B)\!\to\!(II),\ (C)\!\to\!(I),\ (D)\!\to\!(III)$ |