The de-Broglie wavelength associated with a ball of mass 150 g traveling at 30.0 m/s would be

$1.47 × 10^{-34} m$

The correct answer is Option (1) → $1.47 × 10^{-34} m$

Given:

Mass, $m = 150\,g = 0.15\,kg$

Velocity, $v = 30\,m/s$

Formula: $\lambda = \frac{h}{mv}$

where $h = 6.63 \times 10^{-34}\,Js$

$\lambda = \frac{6.63 \times 10^{-34}}{0.15 \times 30}$

$\lambda = \frac{6.63 \times 10^{-34}}{4.5}$

$\lambda = 1.47 \times 10^{-34}\,m$

Therefore, the de-Broglie wavelength of the ball is $1.47 \times 10^{-34}\,m$.